explain with answer both questions
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1).
A particle is dropped from the top of a tower. During its motion it covers 25/9 part of height of tower the last 1 seconds. Then find the height of tower?
WHICH GIVES T=5 SEC
(TIME CANNOT BE NEAGITIVE)
2)
Two tall building face each other and are at a distance of 180 m from each other. With what velocity must a ball be thrown horizontally from a window 55 m above the ground in one building, so that it enters a window 10.9 m above the ground in the second building?
Height = h= 55-10.9 = 44.1
Distance= s= 180 m
time taken = t
so, h=1/2 gt²
or t= √2h/g
√2 x 44.1/9.8
=√88.2/9.8
=√9 = 3
S= velocity x t
180= velocity x 3
velocity =180/3 = 60 m/s
Hope it helps you❤️
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