explain with steps to find the splitting the middle term of these questions 12xsquare+-7x+1,2xsquare+7x+3,square
Answers
Answered by
0
Answer:
12x^2-7x+1=0
12x^2-4x+3x+1=0
4x(3x+1)+1(3x+1)=0
3x+1=0,4x+1=0
3x=-1,4x=-1
x=-1/3,-1/4
2x^2+7x+3=0
2x^2+6x+1x+3=0
2x(x+3)+1(x+3)=0
x+3=0,2x+1=0
x=-3,-1/2
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
hey!!
Factorise:
(i) 12x2−7x−1
(ii) 2x2+7x+3
(iii) 6x2+5x−6
(iv) 3x2−x−4
ANSWER
(i) 12x2−7x+1
=12x2−4x−3x+1
=4x(3x−1)−1(3x−1)
=(4x−1)(3x−1)
(ii) 2x2+7x+3
=2x2+6x+x+3
=2x(x+3)+1(x+3)
=(2x+1)(x+3)
(iii) 6x2+5x−6
=6x2+9x−4x−6
=3x(2x+3)−2(2x+3)
3)−2(2x+3)
=(3x−2)(2x+3)
(iv)) 3x2−x−4
=3x2−4x+3x−4
=x(3x−4)+1(3x−4)
=(3x−4)(x+1)
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