Explain (x+y)^2 = x^2+2xy+y^2. is this correct?
Answers
Answered by
2
Heya,
Here is your answer.
- Yeah!! This is indeed correct equation!!
- We have Some Algebraic Identities. There are 4 basic identities.
- ( x+y)^2 = x^3+2xy+y^2 is the first basic identity.
- It can also be in the form (a+b)^2 = a^2+2ab+b^2.
(x+y)^2 = (x+y) (x+y)
(x+y) (x+y) = x^2+y^2 + 2× x × y
= x^2 + y^2 + 2xy
which gives,
- (x+y)^2 = x^2+ 2xy+ y^2.
Hope it helps!!
Here is your answer.
- Yeah!! This is indeed correct equation!!
- We have Some Algebraic Identities. There are 4 basic identities.
- ( x+y)^2 = x^3+2xy+y^2 is the first basic identity.
- It can also be in the form (a+b)^2 = a^2+2ab+b^2.
(x+y)^2 = (x+y) (x+y)
(x+y) (x+y) = x^2+y^2 + 2× x × y
= x^2 + y^2 + 2xy
which gives,
- (x+y)^2 = x^2+ 2xy+ y^2.
Hope it helps!!
Answered by
1
I think it is helpful for you
Attachments:
Similar questions