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Question) If 100g of calcium carbonate on heating produce 44g of carbon dioxide, how much quicklime will be formed? Which no is followed for solving this problem
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this question is based on law of conservation of mass.It states that the mass can neither be created or nor be destroyed during chemical reaction.
therefore,Mass of Calcium Carbonate = Mass of the Carbon dioxide + Mass of quick lime.
So,100g = 44g + Mass of quick lime
Or,Mass of quick lime = (100-44)g
= 56g
Therefore,Mass of quick lime = 56g.
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