Question

Explain zeroth law of thermodynamics using schematic representation.
A 10 f capacitor is connected with 100 V battery what would be electrostatic energy stored? ​

Answer 1

Answer:

The zeroth law of thermodynamics states that if two thermodynamic systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other. Accordingly, thermal equilibrium between systems is a transitive relation.

U= 1/2 CV2

U= 1/2×10×10-4 ×250 2

U=5×10 −4

×250 2

U=31.25J

Answer 2

Explanation 1:

• The Zeroth law of thermodynamics states for a system having variable temperatures .If a system contains 3 components, at temperatures namely $T_{1}$, $T_{2}$ and $T_{3}$ , the zeroth law of thermodynamics states that if the system having temperature $T_{2}$ is in thermal equilibrium with $T_{1}$ and also the system with temperature $T_{3}$ is in thermal equilibrium with $T_{2}$ hence, the systems with temperature $T_{1}$ and $T_{3}$ will be in equilibrium with each other.

Mathematically,

$T_{1}=T_{2}$

$T_{3}=T_{2}$

Hence,

$T_{1} =T_{3}$

For diagram, see the attached image below.

Explanation 2

The charge across a given conductor is directly proportional to the potential difference applied across its end.

$Q$ ∝ $V$

$Q=CV$

Where, $C$ is the capacitance of the conductor. Since, capacitance is directly proportional to the charge stored hence, More is the ability of a capacitor to store charge, more will be its value of capacitance.

The energy stored in the capacitor is given by,

$E=\frac{1}{2} CV^{2}$

According to the question, we have

$C=10F$      $;$  $V=100V$

$E=\frac{1}{2} (10)(100)^{2}$

$E=5$ × $10^{4}J$

Hence, the energy stored in the capacitor is 5 × 10⁴ J.