Question

# Explained answer
@ Linear Equation in two variables.

In a deer park there are some deer and some humans. If the number of head here is 53. The number of legs is 160. Find the number of deer and the number of human​

Answer 1

Answer:

Number of deers are 27 and Number of humans are 26.

Step-by-step explanation:

Given :

• Number of heads is 53.
• Number of legs is 160.

To find :

• Number of deers.
• Number of human.

Solution :

Let, Number of deers be x.

And, Number of human be y.

Number of head deer and human has 1 head each.

• x + y = 53 or 1x + 1y = 53

Number of legs goat and human has 4 and 2.

• 4x + 2y = 160

Let, equations be

• x + y = 53 ---- (i)

• 4x + 2y = 160 ------ (ii)

So, Take equation (i)

→ x + y = 53

→ x = 53 - y ----- (iii)

Then, Put value of x in equation (ii)

→ 4x + 2y = 160

→ 4 × (53 - y) + 2y = 160 [x = 53-y is by eq (iii)]

→ 212 - 4y + 2y = 160

→ 212 - 2y = 160

→ -2y = 160 - 212

→ -2y = -52

→ y = -52/-2

→ y = 26

Now, Put value of y (26) in any equation :

→ x = 53 - y -----(iii)

→ x = 53 - 26

→ x = 27

x and y are number of deers and humans respectively.

Thus,

Number of deers are 27 and number of humans are 26.

Answer 2

Let x be the total no of legs of deer

let y be the total no of legs of visitors.

∴x + y = 132

∵1deer has 4 legs and 1 head & 1 visitor has 2 legs and 1 head

∴x/4 + y/2 = 39

plotting the graph we get the point of intersection which is the value of x and y.

thus from the graph we can say x = 108 and y=24

∴ num of deers = 108/4 = 27

∴ num of visitors = 24/2 = 12