Physics, asked by Anonymous, 11 months ago

✍✍✍✍explanation must required✍✍✍✍ =》》Equation of trajectory of a projectile is given by y=-x square + 10 x where x and y are in meters and x is along horizontal and y is vertically upward and particle is projected from origin. then which of the following option is incorrect (1) initial velocity of particle is √505 m/s (2) horizontal range is 10m (3) maximum height is 25 m (4) angle of projection with horizontal is tan^-1theta

Answers

Answered by Anonymous
3

(2) horizontal range is 10m

Comparing y = 10x-x² = 10x(1-x/10)

with the standard equation of trajectory y = xtan∅(1-x/R) , we get than

tan∅ = 10 and R = 10m

Answered by KINGofDEVIL
2

ANSWER :

H range = 10.

By comparing with the equition of trajectory we get,

tan theta = 10 and R = 10m

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