Math, asked by piyu6642, 5 hours ago

Explanation of given 4 questions

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Answers

Answered by amritaydv65
0

Answer:

ಶ್ರೀಪಂಡಿತಾರಾಧ್ಯ

Step-by-step explanation:

Good question Explanation of given 4 questions

Answered by stutimittal0123
0

Step-by-step explanation:

  1. you may have read the identity a²-b²= (a+b)(a-b)

so placing the values of a and b as 98 and 96 respectively

we get,

98²-96²=(98+96)(98-96)

= 194×2

=388

2. in this question we will take 99 as common or we can say factorize it

so,

99²+99= 99(99+1) (as 99×99=99² and 99×1=99 which gives us the same value of the question)

99²+99=99(99+1)

=99(100)

= 9900

3. using identity a²-b²= (a+b)(a-b)

we get,

68²-67²= (68+67)(68-67)

= 135×1

= 135

4. 57 can be written as 60-3

similarly, 63 can be written as 60+3

using identity (a+b)(a-b)=a²-b²

(60+3)(60-3)= (60)²-(3)²

= 3600-9

=3591

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