Question

Explanation:

$<p style="color:cyan;font-family:cursive;background:black;font size:25px;"> KAISE HO AAP LOG$

$\bf \: {x}^{2} - 2x - 5 = 0$
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Answer 1

Answer:

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Answer 2

$\huge{\boxed{\mathfrak{\fcolorbox{black}{pink}{Hello\:mate\:!!!}}}}$

Ham to acche hai aur aap......

${x}^{2}\:-\:2x\:-\:5$

we group our terms like this

$({x}^{2}\:-\:2x\:+something)\:-\:5\:=\:0\:+\:something$

The "something" is always half of the middle term's coefficient squared...here it is 1.

so we have,

$({x}^{2}\:-\:2x\:-1)\:-\:5$

${x-1}^{2}\:-\:5\:=\:1$

${x-1}^{2}\:=\:6$

take square root of both sides now

x - 1 = $\frac{+}{-}\sqrt{6}$

x = 1 $\frac{+}{-}\sqrt{6}$

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