Question

exponents and powers class 8
plz ans all the questions correctly ​

Answer 1

Answer:

1) 49/4

when the exponent is negative, the value we get needs to be reciprocal.

=2×2/7×7

=4/49

After resiprocal, answer is 49/4

2.1) 3

= 3(9-5) × 3-³

= 3⁴×3-³

= 3[4+(-3)]

=3(4-3)

=3¹

=3

2.2) 2401

(-2)⁴×(7/2)⁴

we know that, when exponent is even, the value will become positive

so,

= 2⁴×(7/2)⁴

= 2×2×2×2×7×7×7×7/2×2×2×2

all 2 will get cancel

= 7×7×7×7

= 2401

3) 10

we know that, when exponent is 0, the result will be 1

so, (4^O + 9)×3²

= (1+1/9)×3²

= 10/9×9

both 9 will get cancel

= 10

4) 375

= 27-¹× 5³ / 3-⁴

= 27 & 3 will get reciprocal

= 3⁴ × 5³ / 27

27 can be written as 3×3×3

= 3×3×3×3×5×5×5 / 3×3×3

after canceling 3s only one 3 will be left

= 5×5×5×3

= 375

5) 7

= 3ⁿ / 3² = 3^5

= 3(ⁿ-²) = 3^5

ignoring the 3 bcz we need to find n

= n-2 = 5

= n = 5+2

= n = 7

hope it helps!!

mark it as brainliest:)