Exponents
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1st part, ( -1) power 72, which is equal to 1 and 2nd part, 67 power 4/ 67 power 3, which is equal to 67.
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Here in 1st ques..
[(-1)∧9]∧8
= (-1)∧9*∧8 using (a∧p)∧q= a∧p*q
= (-1)∧64
=1
now in second ques
67∧4 * 1/67∧3
67(∧4-∧3) using a∧p÷a∧q= (a)∧p-∧q
=67
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[(-1)∧9]∧8
= (-1)∧9*∧8 using (a∧p)∧q= a∧p*q
= (-1)∧64
=1
now in second ques
67∧4 * 1/67∧3
67(∧4-∧3) using a∧p÷a∧q= (a)∧p-∧q
=67
If helpful mark as brainliest and don't forget to hit the red hearty button of thanks... :)
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