Question

expree the following linear equation in the form of ax+by+c=0 with x/3+y/4=7​

Answer 1

Step-by-step explanation:

x/3 + y/4 = 7

LHS = x/3 + y/4

=> 4(x) + 3(y) / (3)(4)

=> (4x + 3y) / 12

Equating with RHS,

(4x + 3y) / 12 = 7

Multiplying by 12 on both sides,

4x + 3y = 7(12)

=> 4x + 3y = 84

=> 4x + 3y - 84 = 0

Here,

a = 4

b = 3

c = -84