Question

Express 0.12bar3 in the form of p upon q where p and q are integers and cube is not equal to zero.

Answer 1

Heya !!!



0.123( bar on 3)


Let X = 0.123 ( bar on 3)



Then X = 0.1233 --------(1)



Multiply equation (1) by 100 we get,



100X = 12.33 --------(2)


Again multiply equation (2) by 10 we get,



1000X = 123.33 -------(3)



Subtract equation (2) from equation (3) we get,




1000X = 123.33

100X = 12.33

____________


900X = 111


X = 111/900



Hence,



0.123 ( bar on 3) is in the form of 111/900 which is in the form of P/Q.




HOPE IT WILL HELP YOU..... :-)

Answer 2

Answer:

there you go! hope it helps you!