Question

Express 0.23 (3bar) in p/q form

Answer 1

hello friend
here is the answer of ur question:

0.23 bar
let x = 0.2333...
multiply by 10 we get
10x = 2.333....
x= 0.2333....

by subtracting we get,
10x - x = 2.333... - 0.2333...
9x = 2.1

divide by 9
x= 2.1/9

to remove decimal add zero in denominator we get
21/90

hope it helps...!!

Answer 2

Hellooo..

So we need to express 0.2333... in p by q form...

Lets take x = 0.2333... -------- eqn 1

The number of numbers repeated is 1... 

So lets multiple eqn 1 with 10...( as one number is repeated, we add one zero )

So, 10x = 2.333... -------- eqn 2

Now lets subtract eqn 1 from 2 

         10x = 2.3333... 
             x = 0.2333...
     ________________

          9x = 2.100....

         => x = 2.1 / 9
         => x = 2.1 × 10 / 9 × 10 ( we mulitply with 10 inorder to remove the decimal )
         => x = 21 / 90

Hope it helps ....

And here CutieBarbie :)