express 0.235 bar in the form of p/q form , where p nd q are integers nd q≠0.
Answers
Answered by
13
Hlo friend ...
Nice question..
Here is ur answer :
0.235 bar
Let x = 0.235 bar_ _ _ _ _ _ _ _ _ _ eq(1)
Multiply by 1000 on both sides
1000x = 235.235 bar_ _ _ _ _ _ _ _ eq(2)
Subtract eqⁿ (2) - eq ⁿ(1)
1000x - x = 235.235 bar - 0.235 bar
999x = 235
x = 235/999
0.235 bar = 235/999
HOPE IT HELPS YOU...
REGARDS
@sunita
Nice question..
Here is ur answer :
0.235 bar
Let x = 0.235 bar_ _ _ _ _ _ _ _ _ _ eq(1)
Multiply by 1000 on both sides
1000x = 235.235 bar_ _ _ _ _ _ _ _ eq(2)
Subtract eqⁿ (2) - eq ⁿ(1)
1000x - x = 235.235 bar - 0.235 bar
999x = 235
x = 235/999
0.235 bar = 235/999
HOPE IT HELPS YOU...
REGARDS
@sunita
Answered by
15
Answer is 233 / 990
Solution :
Let x =
⇒ x = 0. 23 53 53 535........( i )
Multiply both sides by 10,
⇒ 10x = 2. 35 35 35 35...... ( ii )
Multiply both sides by 100,
⇒ 1000 x = 235. 35 35 35...... ( iii )
On subtracting ( ii ) from ( iii )
1000 x - 10 x = 235 - 2
⇒ 990 x = 233
⇒ x =
Therefore,
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