Express 0.252 bar in the form p / q where p and q are integers and q is not equal to zero
Kiyara1:
252upon1000
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Answered by
21
let x = 0.252 ......(1)
then, 1000x = 252.......(2)
subtracting equation 2 from 1, we get
999x = 252
=> x = 252/999
Hence , 252/999 is the number which is in the form p/q where p and q are integers and q is not equal to 0 .
Hope it will help.
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then, 1000x = 252.......(2)
subtracting equation 2 from 1, we get
999x = 252
=> x = 252/999
Hence , 252/999 is the number which is in the form p/q where p and q are integers and q is not equal to 0 .
Hope it will help.
please mark as braienliest.
THANKS.
Answered by
2
Let x = 2.252 bar____eq.1
1000x = 2252.252______eq.2
Subtracting eq. 1 from 2
1000x - x = 2252.252 - 2.252
999x = 2250
x = 2250/999
x = 250/111
1000x = 2252.252______eq.2
Subtracting eq. 1 from 2
1000x - x = 2252.252 - 2.252
999x = 2250
x = 2250/999
x = 250/111
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