Math, asked by sureus8933, 9 months ago

Express 0.32 (bar i on 2 only) in the form p/q

Answers

Answered by MisterIncredible
3

\huge{\tt{\red{\underline{\underline{\blue{\overline{\overline{\green{ANSWER}}}}}}}}}

\underline{\large{\mathbb{G}{i}{v}{e}{n}}}

0.32 ( bar is on 2)

\rule{400}{2}

\mathsf{\large{Required\;to\;find  \: : }}

\longrightarrow{ Express \; in \; the \; form \; of \; \dfrac{p}{q}}

\rule{400}{2}

Explanation :

Before solving this question we need to know what is meant by period and periodicity .

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What is period ?

In simple terms , we can say that the numbers which are repeating or recurring in that expansion .

For example :

Find the period of 3.33333-----

Here, the recurring Digit in that expansion is 3 .

So,

\red{\Rightarrow{\tt{Period = 3 }}}

\rule{400}{1}

What is periodicity ?

In simple terms , we can say that the no. of digits ( here digits refers to numbers ) which are repeating/recurring in that expansion .

For example :

Find the periodicity of 9.35353535----

Here, the no. of digits which are repeating is 2

So,

\blue{\Rightarrow{\tt{Periodicity = 2}}}

In this type of questions periodicity plays an major role in the solution .

The major role .

Depending upon the number of digits recurring we have to choose the number which should be multipled .

For example :

If Periodicity is 2 .

The number which should be multipled is 100 .

If Periodicity is 1 .

The number which should be multipled is 10 .

Depending on the Periodicity the number of zeros will get increased .

Knowing this concept is important to Solve questions like this .

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Solution :

Given number :

0.32222---

0.32 ( bar is on 2)

Here,

\boxed{\tt{period \:  = 2}}

\boxed{\tt{ periodicity = 1}}

Since,

The Periodicity is 1 the number which is needed to be multipled is 10 .

Hence,

Let's consider

\orange{x = 0.3222------}{\longrightarrow{\tt{Equation\; - \;1 }}}

Multiply with 10 on both sides ..

\green{10(x) = 10(0.32222-----)}

consider this as ;

\green{10x = 3.2222------}{\longrightarrow{\tt{Equation\; - 2\;}}}

However,

Subtract equation 1 from 2

\tt{\green{10x = 3.2222------}}

\tt{\orange{ \:  \:  \:  \:  \: x = 0.3222------}}

\rule{90}{2}

\tt{9x = 2.9000--- }

\tt{\Rightarrow{ x = \dfrac{2.9}{9}}}

\tt{Multiply\: Numerator\: and\: denominator \: with \: 10}

\tt{\Rightarrow{ x = \dfrac{2.9}{9} \times \dfrac{10}{10}}}

\tt{\implies{ x = \dfrac{29}{90}}}

The p/q form of 0.3222-- is

\blue{\boxed{\longrightarrow{\therefore{0.322--- \:=\: \dfrac{29}{90}}}}}

\rule{400}{2}

✅ Hence Solved ...

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