Question

Express 0.34 bar - 0.2bar + 0.6 bar in the form of p by q

Answer 1

0.34 bar

Let x = 0.343434..........(i)

100x = 34.3434..........(ii)

(ii) - (i) = (34.3434...) - (0.3434...)

=> 100x - x = 34

=> 99x = 34

=> x = 34/99

Now,

0.2 bar

Let, y be 0.22222.......(i)

10y = 2.22222........(ii)

(ii) - (i) = (2.222...) - (0.222...)

=> 10y - y = 2

=> 9y = 2

=> y = 2/9

Now,
0.6 bar

Let, z be 0.6666...........(i)

10z = 6.6666............(ii)

(ii) - (i) = (6.666...) - (0.666...)

=> 10z - z = 6

=> 9z = 6

=> z = 6/9 = 2/3

Now,

$\frac{34}{99} + \frac{2}{9} + \frac{2}{3} \\ \\ = \frac{34 + 22 + 66}{99} \\ \\ = \frac{122}{99}$