express 0.352[52 bar] in the form of p/q
Answers
Answered by
18
Let x =0.352
x=0.352525252
Here:
period=3
periodicity=2
So multiply both sides by 100.
100 x=35.2525252.....................
x= 0.3525252.....................
------------------------------------------------
99x = 34.9000000....................
------------------------------------------------
99x=34.9
x =349
---------
99
HOPE HELPS
PLzzz mrk as brainliest..........
x=0.352525252
Here:
period=3
periodicity=2
So multiply both sides by 100.
100 x=35.2525252.....................
x= 0.3525252.....................
------------------------------------------------
99x = 34.9000000....................
------------------------------------------------
99x=34.9
x =349
---------
99
HOPE HELPS
PLzzz mrk as brainliest..........
mspkkavya:
plss mrk as brainliest answer
Answered by
17
Let x = 3.5252525252........... -------(1)
multiply both sides with 100
100x = 352.5252525252...... -------(2)
subtract equation (2) - (1) .
100x - x = 352.525252..... - 3.525252.....
99x = 349
x = 349/99
hence, 349/99 is the form of P/Q of 3.52[ 52bar ]
multiply both sides with 100
100x = 352.5252525252...... -------(2)
subtract equation (2) - (1) .
100x - x = 352.525252..... - 3.525252.....
99x = 349
x = 349/99
hence, 349/99 is the form of P/Q of 3.52[ 52bar ]
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