Express 0.47, (in which 7 is repeating)in the form of p/q
Answers
Answer:
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Step-by-step explanation:
<br> (ii) Let x=0.888……. <br> On multiplying both sides of Eq.(i) by 10 we, get <br> 10 x. 8.888……. <br> On subtracting Eq. (i) from Eq. (ii),we get <br> 10x-x=(8.88) - (0.888) <br> 9x=8 <br>
<br> (iii) Let
<br> On multiplying both sides of Eq. (i) by 10, we get <br> 10x=52.222...... <br> On subtracting Eq. (i) from Eq. (ii) , we get <br> 10x-x=(52.222.....)-(5.222......) <br> 9x =47 <br>
<br> (v) Let
<br>
<br> On multiply both sides of Eq. (i) by 1000, we get <br> 1000x=001.001..... <br> On subtrating Eq. (i) from Eq. (ii) we, get <br>
<br> 999x = 001 <br>
<br> Let x= 0.2555...... <br> On multplying both sides of Eq. (i) by 10, we get <br> 10x=2.555.... <br> On multiplying both sides of Eq. (ii) by 10, we get <br> 100x=25.55...... <br> On subtracting Eq. (ii) from Eq. (iii) , we get <br> 100x-10x=25.55...-(2.555...) <br> 90x=23 <br>
<br> (vi) Let
<br>
<br> On multiplying both sides of Eq. (i) by 10, we get <br> 10x=13434......... <br> On multplying both sides of Eq. (ii) by 100 , we get <br> 1000x= 134.3434......... <br> On subtracting Eq. (ii) from Eq. (iii) we, get <br> 100x-10x= 134.34..... -(1.3434....) <br> 990x=133 <br>
<br> (vii) Let x= 0.00323232 <br> On Multiplying both sides of Eq. (i) by 100 we get <br> 100x = 0.3232...... <br> On multiplying both sides of Eq. (ii) by 100 , we get <br> 1000x=32.3232......... <br> On subtracting Eq. (ii) [from Eq. (iii) we get <br> 1000x-100x=32.32 ......-0.3232....... <br> 9900x=32 <br> x=
[dividing numerator and denominator by 4] <br> (viii) Let x=0.404040. <br> On multiplying both sides of eq. (i) by 100, we get <br> 100x = 40.4040 <br> On subtracting Eq. (i) from (ii),we get <br> 100x -x =40.4040 ...... - 0.404040....... <br> 99x =40 <br>
<br> (ii) Let x=0.888……. <br> On multiplying both sides of Eq.(i) by 10 we, get <br> 10 x. 8.888……. <br> On subtracting Eq. (i) from Eq. (ii),we get <br> 10x-x=(8.88) - (0.888) <br> 9x=8 <br>
<br> (iii) Let
<br> On multiplying both sides of Eq. (i) by 10, we get <br> 10x=52.222...... <br> On subtracting Eq. (i) from Eq. (ii) , we get <br> 10x-x=(52.222.....)-(5.222......) <br> 9x =47 <br>
<br> (v) Let
<br>
<br> On multiply both sides of Eq. (i) by 1000, we get <br> 1000x=001.001..... <br> On subtrating Eq. (i) from Eq. (ii) we, get <br>
<br> 999x = 001 <br>
<br> Let x= 0.2555...... <br> On multplying both sides of Eq. (i) by 10, we get <br> 10x=2.555.... <br> On multiplying both sides of Eq. (ii) by 10, we get <br> 100x=25.55...... <br> On subtracting Eq. (ii) from Eq. (iii) , we get <br> 100x-10x=25.55...-(2.555...) <br> 90x=23 <br>
<br> (vi) Let
<br>
<br> On multiplying both sides of Eq. (i) by 10, we get <br> 10x=13434......... <br> On multplying both sides of Eq. (ii) by 100 , we get <br> 1000x= 134.3434......... <br> On subtracting Eq. (ii) from Eq. (iii) we, get <br> 100x-10x= 134.34..... -(1.3434....) <br> 990x=133 <br>
<br> (vii) Let x= 0.00323232 <br> On Multiplying both sides of Eq. (i) by 100 we get <br> 100x = 0.3232...... <br> On multiplying both sides of Eq. (ii) by 100 , we get <br> 1000x=32.3232......... <br> On subtracting Eq. (ii) [from Eq. (iii) we get <br> 1000x-100x=32.32 ......-0.3232....... <br> 9900x=32 <br> x=
[dividing numerator and denominator by 4] <br> (viii) Let x=0.404040. <br> On multiplying both sides of eq. (i) by 100, we get <br> 100x = 40.4040 <br> On subtracting Eq. (i) from (ii),we get <br> 100x -x =40.4040 ...... - 0.404040....... <br> 99x =40 <br>
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