Question

express 0.477777.....…..in the form of p q where p and q are integers and p#0​

Answer 1

Answer:

see this dear

Explanation:

Letx=0.4747...−−−(1)

Multiply equation (1) by 100 , we get

\implies 100x=47.4747...--(2)⟹100x=47.4747...−−(2)

Subtract equation (1) from equation (2), we get

\implies 99x=47⟹99x=47

\implies x = \frac{47}{99}⟹x=

99

47

Therefore,

0.474747....=\frac{47}{99}0.474747....=

99

47