Question

Express 0.6+0.7bar+0.47bar in the form of p/q ,where pand q are integers anq is not equal to 0

Answer 1

Solution :-

Let x = 0.7Bar

⇒ x = 0.777..........  .........(1)

Multiplying (1) by 10 

⇒ 10x = 7.7...... = 7.777 ...........(2)

Subtracting (1) from (2)

⇒ 10x - x = 9x
 
⇒ 7.777 - 0.777 = 7
    
⇒ 9x = 7 

⇒ x = 7/9

Let y = 0.47Bar

⇒ y = 0.4747 ..............  ........(1)

Multiplying (1) by 100 

⇒ 100y = 47.4747  ............(2)

Subtracting (1) from (2)

⇒ 100y - y = 99y

⇒ 47.4747 - 0.4747 = 47

⇒ 99y = 47

⇒ y = 47/99

Now,

0.7Bar = 7/9

and 0.47Bar = 47/99

0.6 = 6/10

6/10 + 7/9 + 47/99

Taking L.C.M. of the denominator and then solving it, we get.

⇒ (594 + 770 + 470)/990

⇒ 1834/990

⇒ 917/495

Hence, 0.6 + 0.7Bar + 0.47Bar = 917/495

Answer.

Answer 2

The answer is 917/495.

Hope this will help you.....