CBSE BOARD XII, asked by aloksheeran, 1 year ago

Express 0.6 bar + 0.7 bar + 0.8 by in the form P by q

Answers

Answered by WritersParadise01
34
ANSWER :-
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let x = 0.6666....

so, 10x = 6.666....

then,

10x - x = 6.666.... - 0.666....

=> 9x = 6

=> x = \frac{6}{9}

=> x = \frac{2}{3}

so, o.6666.... in p/q form is \frac{2}{3}.

now, let y = 0.7777....

so, 10y = 7.777...

then,

=> 10y - y = 7.777... - 0.777....

=> 9y = 7

=> y =  \frac{7}{9}

so, 0.777... in p/q form is \frac{7}{9}

Now, let z = 0.888...

so, 10z = 8.888....

then,

=> 10z - z = 8.888... - 0.888...

=> 9z = 8

=> z = \frac{8}{9}

so, 0.888... in p/q form is  \frac{8}{9}.

thus, addition of these terms are :-

= \frac{2}{3} +   \frac{7}{9} +  \frac{8}{9}

=  \frac{6+7+8}{9}

=  \frac{21}{9}

=  \frac{7}{3} ...... answer!
Answered by sampriyesh
0

Answer:

7/3 Is the answer

Explanation:

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