Express 0.6 bar + 0.7 bar + 0.8 by in the form P by q
Answers
Answered by
34
ANSWER :-
-----------------
let x = 0.6666....
so, 10x = 6.666....
then,
10x - x = 6.666.... - 0.666....
=> 9x = 6
=> x =
=> x =
so, o.6666.... in p/q form is .
now, let y = 0.7777....
so, 10y = 7.777...
then,
=> 10y - y = 7.777... - 0.777....
=> 9y = 7
=> y =
so, 0.777... in p/q form is
Now, let z = 0.888...
so, 10z = 8.888....
then,
=> 10z - z = 8.888... - 0.888...
=> 9z = 8
=> z =
so, 0.888... in p/q form is .
thus, addition of these terms are :-
= + +
=
=
= ...... answer!
-----------------
let x = 0.6666....
so, 10x = 6.666....
then,
10x - x = 6.666.... - 0.666....
=> 9x = 6
=> x =
=> x =
so, o.6666.... in p/q form is .
now, let y = 0.7777....
so, 10y = 7.777...
then,
=> 10y - y = 7.777... - 0.777....
=> 9y = 7
=> y =
so, 0.777... in p/q form is
Now, let z = 0.888...
so, 10z = 8.888....
then,
=> 10z - z = 8.888... - 0.888...
=> 9z = 8
=> z =
so, 0.888... in p/q form is .
thus, addition of these terms are :-
= + +
=
=
= ...... answer!
Answered by
0
Answer:
7/3 Is the answer
Explanation:
Similar questions
Science,
7 months ago
English,
7 months ago
Math,
1 year ago
Math,
1 year ago
India Languages,
1 year ago