Question

express 0.621 bar and 125.3bar in the form of p by q​

Answer 1

0.621 bar

let 0.621 bar be x

x=0.621621621....

multiply 1000 by both the sides

1000 × x = 0.621621621...×1000

1000x = 621.621621...

subtract the above two equations

1000x - x = 621.621621....-0.621621...

999x = 621

x=621/999

x=207/333

x=69/111

125.3 bar

let 125.3 bar be x

x = 125.333....

multiply would by both the sides

10 × x = 125.333...×10

10x = 1253.333...

subtract the above two equations

10x - x = 1253.333...×125.333...

9x = 1128

x=1128/9

x=376/3

Answer 2

Refer to the attachment

#hope it helps....