Question

Express 0.8 bar + 0.7 bar + 0.43 bar in the form p/q

Answer 1

0.8 bar we can represent like this
0.8+0.08+0.008+0.0008..........
so it is in G.P
so
a = 0.8
r = T2/T1 = 0.08/0.8 = 0.1
S(infinity) = ?

S(infinity) = a/(1-r)
S(infinity) = 0.8/(1-0.1)
S(infinity) = 0.8/0.9
S(infinity) = 8/10/9/10
S(infinity) = 8/10×10/9
S(infinity) = 8/9

0.7 bar we can represent like this
0.7+0.07+0.007+0.0007
so it is in G.P
so
a = 0.7
r = 0.1
S(infinity) = ?

S(infinity) = a/(1-r)
S(infinity) = 0.7/(1-0.1)
S(infinity) = 7/10/9/10
S(infinity) = 7/10×10/9
S(infinity) = 7/9

0.43 barber can represent like this
0.43+0.0043+0.000043.................
so it is in G.P
so
a = 0.43
r = 0.01
S(infinity) = ?

S(infinity) = a/(1-r)
S(infinity) = 0.43/(1-0.01)
S(infinity) = 43/100/99/100
S(infinity) = 43/100×100/99
S(infinity) = 43/99

so
0.8 bar + 0.7 bar + 0.43 bar
= 8/9+7/9+43/99
= (8+7)/9+43/99
= 15/9+43/99
= (15×11)/99
= 165/99

so your answer is 165/99

Answer 2

Answer:

165 / 99 I think this hope it help you