Express 0.99999..... in the form of p upon q Answer plzz
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Answered by
1
Hope it helps....!!!!
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Let x=0.99999....
There is only one repeating digit so multiply by 10 we get:
10x=9.9999....
x=0.9999...
Subtract x now we get
9x=9
Divide by 9 we get
x=9/9=1
Thus 0.99999=1
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#Be Brainly✌️
_____________
Let x=0.99999....
There is only one repeating digit so multiply by 10 we get:
10x=9.9999....
x=0.9999...
Subtract x now we get
9x=9
Divide by 9 we get
x=9/9=1
Thus 0.99999=1
________________
#Be Brainly✌️
rishuawasthi:
thankyouuu
Answered by
2
Given:
0.9 = 0.99999…
Let x = 0.99999……. (1)
Here only one digit is repeating so multiply by 10 on both sides
10 × x = 10× 0.99999….
10x = 9.9999…. (2)
On subtracting equation 1 from equation 2
10x- x = 9.9999…. - 0.9999….
9x = 9
x = 9/ 9 = 1
Here , 0.9 = 1
0.9 = 0.99999…
Let x = 0.99999……. (1)
Here only one digit is repeating so multiply by 10 on both sides
10 × x = 10× 0.99999….
10x = 9.9999…. (2)
On subtracting equation 1 from equation 2
10x- x = 9.9999…. - 0.9999….
9x = 9
x = 9/ 9 = 1
Here , 0.9 = 1
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