express 1/1+√2-√3 with rational denominator
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Hi ,
1/ ( 1 + √2 - √3 )
= ( 1 +√2+√3)/[(1+√2-√3)(1+√2+√3)]
= (1+√2+√3)/[(1+√2)² - (√3)² ]
= ( 1+√2+√3)/[ 1+2+2√2-3 ]
= ( 1+√2+√3)/ ( 2√2)
= [ √2(1 + √2 + √3 )]/( 2√2 × √2 )
= ( √2 + 2 + √6 ) / 4
I hope this helps you.
:)
1/ ( 1 + √2 - √3 )
= ( 1 +√2+√3)/[(1+√2-√3)(1+√2+√3)]
= (1+√2+√3)/[(1+√2)² - (√3)² ]
= ( 1+√2+√3)/[ 1+2+2√2-3 ]
= ( 1+√2+√3)/ ( 2√2)
= [ √2(1 + √2 + √3 )]/( 2√2 × √2 )
= ( √2 + 2 + √6 ) / 4
I hope this helps you.
:)
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