express 1/1+√2-√3 with rational denominator.
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Given 1/[(1 + √2) - √3 ] rationalise the denominator ⇒ [(1 + √2) + √3 ] / [(1 + √2) - √3 ] [(1 + √2) + √3 ] ⇒ [(1 + √2) + √3 ] / [(1 + √2)2 - 3 ] ⇒ [(1 + √2) + √3 ] / [2√2 ] rationalise the denominator with √2 ⇒ √2[(1 + √2) + √3 ] / 4 ⇒ (√2 + 2 + √6 ] / 4
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