Question

Express 1.127 bar (bar only on 27) in the form of p by q where p and q are integers and q is not equal to zero

Answer 1

Let x = 1.1272727....


100x = 112.72727...

100x = 112.727272.....
(-) x = 1 .1272727......
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99x = 111.6000

x = 111.6/99

x= 1116/990

x = 124/110

Hope it helps u : )

Answer 2

Hello here ,,

Solution ≈
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Given = 1.127 (bar on 27)

$let \: \: x = 1.127 \: \: (bar \: \: on \: 27) \\ \\ x = 1.1272727 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ........(1) \\ 10x = 11.272727 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .........(2) \\ and \: \: 1000x = 112.2727 \: \: \: \: \: \: \: \: ....(3) \\ \\ subtract \: \: \: (2)from \: (3) \\ we \: get \\ \\ 990x = 101 \\ \\ = > x = \frac{101}{990}$
THEREFORE ,

1.127 = 101/ 990
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Answer .

Hope it's helps you.
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