Express 1.127 bar (bar only on 27) in the form of p by q where p and q are integers and q is not equal to zero
Answers
Answered by
20
Heya !!
Here is your answer.
Given :
1.1272727.....
Let x = 1.127272.....
Multiply by 10
10x = 11.272727.... (i)
Repeat until you get same repeating block after decimals....
1000x = 1127.272727...... (ii)
Now, Subtract (I) from (ii).
1000x = 1127.27272....
10x =. 11.27272....
--------------------------------
990x = 1116
x = 1116/990 = 372/330
= 62/55
Hope You Got IT
Here is your answer.
Given :
1.1272727.....
Let x = 1.127272.....
Multiply by 10
10x = 11.272727.... (i)
Repeat until you get same repeating block after decimals....
1000x = 1127.272727...... (ii)
Now, Subtract (I) from (ii).
1000x = 1127.27272....
10x =. 11.27272....
--------------------------------
990x = 1116
x = 1116/990 = 372/330
= 62/55
Hope You Got IT
Anonymous:
Nice bro
Answered by
8
Hay!!
Dear friend -
_________________________________
Let 1.1272727= x
So,
11.2727= 10x
And 1127.2727 = 1000x
If we subtract it then,
10x form 1000x = 1127.2727-11.2727
=> 990x = 1116
=> x = 1116/990
=> x = 372/330
=> x = 62/55
I hope it's help you
Dear friend -
_________________________________
Let 1.1272727= x
So,
11.2727= 10x
And 1127.2727 = 1000x
If we subtract it then,
10x form 1000x = 1127.2727-11.2727
=> 990x = 1116
=> x = 1116/990
=> x = 372/330
=> x = 62/55
I hope it's help you
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