express (1+2i) (1+i) in the form of a+ib
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Answered by
1
Answer:
(1+2i)/ 1- 2 +2i
= (1+2i)/ -1 +2i
= { (1+2i)/ -1 +2i} X (-1 -2i)/ (-1 -2i)
= {(1+2i) X (-1 -2i)}/1. - 4i^2
=(-1 -2i -2i -4 i^2)/(1. +4)
=( -1 +4 -4i)/5
= 3/5. -(4/5) i
Step-by-step explanation:
hope this helps
Answered by
2
Answer:
1+2i+I+2i^2
1+3i-2
-1+3i
Step-by-step explanation:
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