Question

express 1.32 bar +0.35 bar as a fraction in the simplest form

Answer 1

$\textbf{\underline{Answer :}}$

Let, x = 1.32 (bar on 32)

So, x = 1.323232...

Then, 100x = 132.323232...

Now, 100x - x = 132.323232... - 1.323232...

or, 99x = 131

or, x = 131/99

So, 1.32 (bar on 32) = 131/99 [a fraction]

Again, let, y = 0.35 (bar on 35)

So, y = 0.353535...

Then, 100y = 35.353535...

Now, 100y - y = 35.3535... - 0.3535..

or, 99y = 35

or, y = 35/99

So, 0.35 (bar on 35) = 35/99 [a fraction]

Therefore, 1.32 (bar on 32) + 0.35 (bar on 35)

= 131/99 + 35/99

= (131 + 35)/99

= 166/99,

which is the required fraction.

#$\textbf{MarkAsBrainliest}$

Answer 2

Answer: The answer is $1.3232.... =$ $\frac{131}{99}$ and $0.3535.... = \frac{35}{99}$ . The simplest form of 1.32bar+0.35bar = $\farac{166}{99}$

Step-by-step explanation:

Step 1: Finding the simplest form of 1.32 bar

Let x be the variable

$x = 1.32bar\\x = 1.3232.....----1\\100x = 132.3232....----2\\\\equations (2)-(1)\\100x - x = 132.323232.....-1.323232....\\99x = 131\\x = \frac{131}{99}$

Step 2: Finding the simplest form of 0.35 bar

$x = 0.35bar\\x = 0.3535.....----1\\100x = 35.3535....----2\\\\equations (2)-(1)\\100x - x = 35.353535.....-0.353535....\\99x = 35\\x = \frac{35}{99}$

Step 3: The simplest form of 1.32 bar + 0.35 bar

from above 2 steps

$1.32bar+0.35bar = \frac{131}{99}+\frac{35}{99}\\1.32bar+0.35bar = \frac{166}{99}$