Question

Express 1.3222... + 0.3555... in p/q form ​

Answer 1

Step-by-step explanation:

Let x = 1.32( bar on 2)

x = 1.3222............ ------(1)

Multiply eq 1 by 10

10x =10 × 1.3222

10x = 13.2222…… ------(2)

Multiply eq 2 by 10

10 × 10x = 10 × 13.2222…...

100x = 132.2222…… ------(3)

Subtract eq 2 from 3

100x - 10x =132.2222 - 13.2222

90x = 119

x= 119/90

Let y = 0.35 (bar on 35)

y = 0.353535........ -------(1)

Multiply eq 1 by 100

100y = 35. 353535..... -----(2)

Subtract eq (1) from (2)

100y - y = 35. 353535 - 0.353535

99 y = 35

y = 35 / 99 ----------(3)

GIVEN: 1. 32 (bar on 2) + 0.35 (bar on 35)

x + y

Put the value of x and y from above

= 119 / 90 + 35 / 99

= (119× 11 + 35 × 10) / 990

= (1309 + 350)/990

= 1659/990

= 553/330

Hence, the value is 553/330.

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Answer 2

Answer:

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