Question

Express 1.3222....and 0.3535....as a fraction in simplest form

Answer 1

Hey...

1.32(32 recurring) + 0.35( 35 recurring ) 
Le X= 1.323232323232323232.......(I) 
and 100X= 132.32323232323232323232......(II) Subtracting (I) from (II) gives 
99X=131 or X= 132/99 
Similarly let 
Y= 0.35353535353535.........(III) 100Y = 35.35353535353535353535......(IV) 
Subtracting (III) from (IV) gives 
99Y = 35 or Y= 35/99 
Hence 
1.32(32 recurring) + 0.35( 35 recurring ) 
=131/99+35/99= (131+35)/99= 166/99

Hope this helps..!!

Answer 2

I hope all steps are clear