Question

Express 1.32bar+0.35bar in the form of p/q where p and q are integers and q is not equal to 0

Answer 1

I hope it will help you

Answer 2

Answer:

166/99 Where, 99 ≠ 0

Step-by-step explanation:

Let,

$x=1.\overline{32}$

$\implies x = 1.32323232......$ ------(1)

By multiplying 100,

$100 x = 132.323232......$ ------(2)

Equation (1) - Equation (1),

We get,

99x = 131,

$\implies x = \frac{131}{99}$

Thus,

$1.\overline{32}=\frac{131}{99}$

Now, let,

$y=0.\overline{35}$

$\implies y = 0.35353535......$ ------(1)

By multiplying 100,

$100 y = 35.35353535......$ ------(2)

Equation (1) - Equation (1),

We get,

99y = 35,

$\implies y = \frac{35}{99}$

Thus,

$0.\overline{35}=\frac{35}{99}$

Hence,

$1.\overline{32}+0.\overline{35}=\frac{131}{99}+\frac{35}{99}=\frac{166}{99}$