Math, asked by nicepeacenice, 5 months ago

express (1+3i)^-1 in the form of a+ib

Answers

Answered by chintamanbhamre000

1

Answer:

−2i⋅1+2i1+2i=1+2i5

(1−2i)−3=(1+2i5)3

=1125(13+(2i)3+3(1)(2i)(1+2i))

=−11−2i125

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