Question

express (1+3i)^-1 in the form of a+ib​

Answer 1

Answer:

−2i⋅1+2i1+2i=1+2i5

(1−2i)−3=(1+2i5)3

=1125(13+(2i)3+3(1)(2i)(1+2i))

=−11−2i125