Express 1.4bar(bar above 4) in the form of p/q
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- we will put x=1.4bar or 1.4... name this as equation 1
- now no of digits in repeating block is 1 therefore multiply equation 1 by 10 on b/s
- now equation 1 becomes
- x×10=1.4×10
- this is equal to 10x=14.4bar name it as equation 2
- now subtract equation 2 from 1
- it becomes10x-x=14.4bar-1.4 bar this will be equal to 9x=13 lastly x=13/9(ans)
i want to tell u that if there are 2 digits in repeating block then you will multiply eq 1 by 100 on b/s and if 3 digits in repeating block then multiply by 1000 to eq 1
this is so simple
read all my procedure
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I Hope it helps you dear friend
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