Express (1+7i) in Eulerian form
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Answer:
( 1 + 7i ) = (√50)е^(i81.87)
Step-by-step explanation:
We are given
1 + 7i
Comparing the 1 + 7i with x + yi we get
x = 1 and y = 7
We know that
r² = x² + y²
Putting values we get
r² = 1² + 7² = 1 + 49 = 50
r² = 50
This implies
r = √50
And we know that
tan(α) = y / x = 7 / 1 = 7
tan(α) = 7
⇒ α = 81.87
We know that
x + yi = r( cos(α) + isin(α) )
So
( 1 + 7i ) = √50( cos(81.87) + isin(81.87) )
And we also know that
rе^(iα) = r( cos(α) + isin(α) )
So
( 1 + 7i ) = (√50)е^(i81.87)
Hence
( 1 + 7i ) = (√50)е^(i81.87)
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