Question

Express 1+cot²θ in terms of tanθ

Answer 1

${cot}^{2} \alpha = \frac{1}{tan ^{2} \alpha }$
$\frac{ {tan}^{2} \alpha + 1}{ {tan}^{2} \alpha }$
$\tan^{2} ( \alpha ) + 1 = sec^{2} \alpha$
$\frac{\sec^{2} ( \alpha )}{ {tan}^{2} \alpha }$



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