Express (1-i)^2(1+i)-(3-4i)^2 in the form a+ib
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I'm junior I don't know the answer
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Step-by-step explanation:
(1-i)^2(1+i)-(3-4i)^2
= (-2i)(1+i)-(9-24i-16)
= -2i+2-9+24i+16
= 9+22i
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