Express 1/i+2/i2+3/i3+5/i4 in the from a/ib
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Answered by
77
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As we know that
i² = -1
i³ = -i
i⁴ = 1
So putting these values
Now taking ( i ) as LCM
Now Multiplying and dividing by ( -i)
Again putting the value of i² here
Hence , a+ib = 3 - 2i
Hope it helps
Answered by
33
Answer:
i² = -1 , i³ = (-i) & i⁴ = 1
using all we get ,
1/i -2 -3/i +5
(1/i -3/i) +3
2/i +3
(2+3i)/i
Rationalizing it we get,
(2+3i)(-i)/(-i)²
(-2i-3i²)
(3-2i) (Ans)
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