express (1-i)³(1+I)in the form of a+i.b
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(1−i)3=−2−2i Explanation: Method 1 - direct evaluation (1−i)3=(1−i)(1−i)(1−i) (i−i)3=(1−2i+i2)(1−i) (i−i)3=(−2i)(1−i) (i−i)3= ...
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Step-by-step explanation:
express (1-i)³(1+I)in the form of a+i.b
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A=1
B=I
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