Question

express -1+i√3 in polar form and exponential form

Pls with steps ​

Answer 1

Answer:

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Step-by-step explanation:

z=-1-i√(3)

This complex number’s polar form is:

|z| = √(1+3) = 2

arg(z) = arctan (√3) = π/3

This can be expressed as: 2(cos(π/3) - isin(π/3))