express -1+i√3 in polar form and exponential form
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good morning your answer
Step-by-step explanation:
z=-1-i√(3)
This complex number’s polar form is:
|z| = √(1+3) = 2
arg(z) = arctan (√3) = π/3
This can be expressed as: 2(cos(π/3) - isin(π/3))
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