Express 1/ root 5 +root 3-root 8 with rational denominators
Answers
Answered by
10
Hi ,
1/( √5 + √3 - √8 )
=(√5+√3+√8)/[(√5+√3-√8)(√5+√3+√8)]
= (√5+√3+√8)/{[(√5+√3)-√8][(√5+√3)-√8]}
= (√5+√3+√8)/[( √5 + √3 )² - ( √8 )² ]
= ( √5+√3+√8 )/[(√5)²+(√3)²+2(√5)(√3) - 8 ]
= ( √5 + √3 + √8 )/[ 5 + 3 +2√15 - 8 ]
= ( √5 + √3 + √8 )/2√15
=[ (√3 +√5 + √8 ) × √15 ]/[ 2√15×√15]
= ( 3√5 + 5√3 + √120 )/30
I hope this helps you.
: )
1/( √5 + √3 - √8 )
=(√5+√3+√8)/[(√5+√3-√8)(√5+√3+√8)]
= (√5+√3+√8)/{[(√5+√3)-√8][(√5+√3)-√8]}
= (√5+√3+√8)/[( √5 + √3 )² - ( √8 )² ]
= ( √5+√3+√8 )/[(√5)²+(√3)²+2(√5)(√3) - 8 ]
= ( √5 + √3 + √8 )/[ 5 + 3 +2√15 - 8 ]
= ( √5 + √3 + √8 )/2√15
=[ (√3 +√5 + √8 ) × √15 ]/[ 2√15×√15]
= ( 3√5 + 5√3 + √120 )/30
I hope this helps you.
: )
Urvish19:
please help me wib thar
with that
√120 = √ ( 2 ×2 × 30 ) = 2√30
is it clear now .
yes thank you so much
you're welcome.
if you dont mind can you tell in which class you are
and board
b coz currently i am solving IIT FOUNDATION BOOKS and i need help regarding may question so any medium through witch i can contaxt you
Answered by
0
Answer:
Similar questions