Math, asked by Urvish19, 1 year ago

Express 1/ root 5 +root 3-root 8 with rational denominators

Answers

Answered by mysticd
10
Hi ,

1/( √5 + √3 - √8 )

=(√5+√3+√8)/[(√5+√3-√8)(√5+√3+√8)]

= (√5+√3+√8)/{[(√5+√3)-√8][(√5+√3)-√8]}

= (√5+√3+√8)/[( √5 + √3 )² - ( √8 )² ]

= ( √5+√3+√8 )/[(√5)²+(√3)²+2(√5)(√3) - 8 ]

= ( √5 + √3 + √8 )/[ 5 + 3 +2√15 - 8 ]

= ( √5 + √3 + √8 )/2√15

=[ (√3 +√5 + √8 ) × √15 ]/[ 2√15×√15]

= ( 3√5 + 5√3 + √120 )/30

I hope this helps you.

: )

Urvish19: please help me wib thar
Urvish19: with that
mysticd: √120 = √ ( 2 ×2 × 30 ) = 2√30
mysticd: is it clear now .
Urvish19: yes thank you so much
mysticd: you're welcome.
Urvish19: if you dont mind can you tell in which class you are
Urvish19: and board
Urvish19: b coz currently i am solving IIT FOUNDATION BOOKS and i need help regarding may question so any medium through witch i can contaxt you
Answered by kavinkarthik792
0

Answer:

 \sqrt{5 +   \sqrt{3 +  \sqrt{8 \\ } }

Similar questions