express 100 as the sum of 10 natural numbers
lcmore:
10*ten times=100
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5
10*10 times=100 I.e. 10+10+10+10+10+10+10+10+10+10=100
Answered by
18
Every perfect square can be expressed as sum of consecutive odd no.s using :
Sum of ' n ' consecutive odd numbers = n²
here 100 is a perfect square, n² is 100
n =10
Thus, 100 can be written as sum of first 10 odd no.s
( 1+3+5+7+9+11+13+15+17+19) = 10² = 100
Observe some more examples:
i ) 1 = 1²
ii ) 1 + 3 = 4 = 2²
iii ) 1 + 3 + 5 = 9 = 3²
iv ) 1+ 3+5+7 = 16 = 4²
v ) 1+3+5+7+9 = 25 = 5²
Hope it helps
;)
mark brainliest if you find this helpful
Sum of ' n ' consecutive odd numbers = n²
here 100 is a perfect square, n² is 100
n =10
Thus, 100 can be written as sum of first 10 odd no.s
( 1+3+5+7+9+11+13+15+17+19) = 10² = 100
Observe some more examples:
i ) 1 = 1²
ii ) 1 + 3 = 4 = 2²
iii ) 1 + 3 + 5 = 9 = 3²
iv ) 1+ 3+5+7 = 16 = 4²
v ) 1+3+5+7+9 = 25 = 5²
Hope it helps
;)
mark brainliest if you find this helpful
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