Express 100 as the sum of 10 odd numbers
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Given 100 can be written as 10^2
According to the property of perfect square, for any natural number n, we have sum of first n odd natural numbers =n^2
Expressing 100 as a sum of 10 odd numbers, we get
81=(10)^2
Here n=10
By applying the law 81=(1+3+5+7+9+11+13+15+17+19)
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Answer:
1+3+5+7+9+11+13+15+17+19=100
(sum of n consecutive odd numbers=n^2)
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