Express 121 as the sum of 11 consecutive odd
natural numbers.
Answers
Answered by
1
1+3+5+7+9+11+13+15+17+19+21 = 121
Thus , 121 is a perfect square.
Answered by
2
121=(11)^2
Therefore 121 is the sum of first 11 odd natural numbers
121=1+3+5+7+9+11+13+15+17+19+21
Hope it helps you
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