express 152 as sum of two consecutive positive integers
Answers
Step-by-step explanation:
Find two consecutive positive integers, sum of whose squares is 365.
Solution:
Let first number be x
Let second number be (x+1)
According to given condition, we have
x2+(x+1)2=365 {(a+b)2=a2+b2+2ab}
⇒x2+x2+1+2x=365
⇒2x2+2x−364=0
Dividing equation by 2, we get
x2+x−182=0
⇒x2+14x−13x−182=0
⇒x(x+14)−13(x+14)=0
⇒(x+14)(x−13)=0
⇒x=13,−14
Therefore first number = 13 {We discard -14 because it is given that number is positive).
Second number = x+1=13+1=14
Therefore two consecutive positive integers are 13 and 14 whose sum of squares is equal to 365.
This is an example you can answer to the question using this formula
Step-by-step explanation:
LET THE TWO NUMBERS BE X AND X+1
SO X+X+1=152
2X+1=152
2X=152-1
2X=151
X=151/2=75.5
X+1=75.5++1
=76.5
ANSWER- 75.5 AND 76.5