Question

Express 192 as a sum of two consecutive positive integer?​

Answer 1

Step-by-step explanation:

• let the two consecutive positive integers be x, x+1
• sum = 192

$x + (x + 1) = 192 \\ 2x + 1 = 192 \\ 2x = 192 - 1 \\ 2x = 191 \\ x = \frac{191}{2} \\ x = 95.5$

other number = 95.5 + 1 = 96.5

Answer 2

Answer:

96+96 are two consecutive integer which sum has 192