Question

Express 2.3333..... In the form p/q where q is not = 0

Answer 1

Answer:

x=2.33333..... ... (1)

multiply in equestion (1) by 10

x

10x=23.333.... ... (2)

subtract 1 from 2

9x=21

x=21/9

x=7/3

Answer 2

Let,

$\longrightarrow x=2.333\dots\quad\quad\dots(1)$

Multiplying by 10,

$\longrightarrow 10x=10\times2.333\dots$

$\longrightarrow 10x=23.333\dots\quad\quad\dots(2)$

Subtracting (1) from (2),

$\longrightarrow 10x-x=23.333\dots\,-2.333\dots$

The decimal part can be ignored itself.

$\longrightarrow 9x=23-2$

$\longrightarrow 9x=21$

Dividing by 9, we get,

$\longrightarrow x=\dfrac{21}{9}$

$\longrightarrow \underline{\underline{x=\dfrac{7}{3}}}$

Now our number is in the form $\dfrac{p}{q}$ where $q\neq0.$